CSCI 3300
Spring 2009
Exercises for Quiz 4

1. If variable p has type char*, then expression *p has type

   1. char
   2. char*
   3. char**
   4. int
   5. int*

   Answer

2. What is the value of variable x after performing the following sequence of statements?

     int x = 50;
     int* p = &x;
     *p = 4;
   

   Answer

3. What is the value of variable x after performing the following sequence of statements?

     int y = 7;
     int x = 35;
     int* p = &x;
     p = &y;
   

   Answer

4. What does jump( ) return, where jump is writtten below, using function jumpHelper?

    void jumpHelper(int x)
    {
      x = x + 1;
    }
   
    void jump()
    {
      int z = 40;
      jumpHelper(z);
      return z;
    }
   

   Answer

5. What does hop( ) return, where hop is writtten below, using function hopHelper?

    void hopHelper(int& x)
    {
      x = x + 1;
    }
   
    void hop()
    {
      int z = 40;
      hopHelper(z);
      return z;
    }
   

   Answer

6. What does romp( ) return, where romp is written below, using function rompHelper?

    void rompHelper(int a, int& b)
    {
      b = a + 2;
      a = b + 1;
    }
    int romp()
    {
      int x = 4;
      int y = 25;
      rompHelper(x,y);
      return x + y;
    }
   

   Answer

7. Which of the following will create an array of 30 integers called Orange in C++?

   1. int[30] Orange;
   2. int* Orange[30];
   3. int Orange[30];
   4. int[] Orange[30];

   Answer

8. Which of the following correctly sets all variables in array Orange from the preceding problem to hold 0?

   1. Orange[30] = 0;
   2. for(int k = 1; k <= 30; k++) Orange[k] = 0;
   3. for(int k = 1; k < 30; k++) Orange[k] = 0;
   4. for(int k = 0; k < 30; k++) Orange[k] = 0;
   5. for(int k = 0; k <= 30; k++) Orange[k] = 0;

   Answer

9. Suppose that array A has been created by statement

     int A[4];
   

   What is in array A after performing the following statements? Work this out carefully.

     for(int i = 0; i < 4; i++) A[i] = i;
     for(int i = 1; i < 4; i++) A[i] = A[i-1] - 1;
   

   1. A[0] = 0, A[1] = 1, A[2] = 2, A[3] = 3.
   2. A[0] = 0, A[1] = -1, A[2] = -2, A[3] = -3.
   3. A[0] = 0, A[1] = -1, A[2] = 0, A[3] = 1.
   4. A[0] = 0, A[1] = 0, A[2] = 1, A[3] = 2.
   5. A[0] = 0, A[1] = 0, A[2] = 0, A[3] = 0.

   Answer